Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A particle is thrown vertically upwards. If its velocity at half of the maximum height is 10 m/s , then maximum height attained by it is (Take g = 10 m / s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
B
Let particle thrown with velocity u and its maximum height is H then \(H - \frac{u^{2}}{2g}\)
When particle is at a height \(\mathrm{H} / \mathrm{Z}\) , then its speed is 10 m/s
From equation v^2 = u^2 + 2gh
\((10)^2 = u^2 - 2g \left| \frac{H}{2} \right| := u^2 - 2g \frac{u^2}{4g}\) u^2 = 200
Maximum height \(\to H - \frac{v^2}{2g} - \frac{200}{2 \times 10} - 10 \ m\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A stone falls from a balloon that is descending at a uniform rate of \(12 \quad 111 \quad 15\) . Th…
A body A is projected upwards with a velocity of \(28 \; m \; i \; s\) . The second body B is proje…
A ball is dropped on the floor from a height of 10 m . It rebounds to a height of 2.5 m . If the ba…
Two bodies of different masses mc and m_n are dropped from two different heights \hat{r} and \(\the…
A body falls freely from rest. It covers as much distance in the last second of its motion as cover…
A stone is dropped into water from a bridge 441 \(\pi\) above the water. Another stone is thrown ve…